This is a fixed version of the task Let's Failcrypt, which had an unintended solution.
Let's Failcrypt allows you to easily generate a certificate for your domain.
We know that admin of crypto.legit-service.ovh uses this service.
Can you trick them into issuing a certificate for this domain without being the owner?
Source code:app.py
import random from os import urandom from flask import Flask, render_template, request, session, send_from_directory from challenge import verify from secrets import flag app = Flask(__name__) app.secret_key = urandom(16) @app.route('/static/bulma.min.css') def css(): return send_from_directory('/code/static/', 'bulma.min.css') @app.route('/') def index(): nonce = hex(random.randint(2 ** 511, 2 ** 512))[2:-1] session['nonce'] = nonce return render_template('index.html', nonce=nonce) @app.route('/verify', methods=['POST']) def verify_access(): try: key = request.form['pubkey'] domain = str(request.form['domain']) nonce = int(session['nonce'], 16) if verify(key, domain, nonce): if domain == "crypto.legit-service.ovh": return render_template('result.html', content=flag) else: return render_template('result.html', content="Sorry, for now we are only able to generate certificates for 'crypto.legit-service.ovh'") else: return render_template('result.html', content="Nice try...") except Exception as e: return render_template('result.html', content="You've broken something...") if __name__ == '__main__': app.run()
challenge.pyfrom Crypto.PublicKey import RSA from Crypto.Util.number import bytes_to_long def get_signature_record(domain): from dnsknife import resolver ans = resolver.query(domain, 'TXT') txt = ans.response.answer[0][0].strings[0] return bytes_to_long(txt) def verify_signature(pubkey, signature, nonce): pubkey = RSA.importKey(pubkey) e, n = pubkey.e, pubkey.n # Don't allow weak keys if e < 65537: return False return pow(signature, e, n) == nonce def verify(pubkey, domain, nonce): return verify_signature(pubkey, get_signature_record(domain), nonce)
Format flagi:
ecsc19{litery_cyfry_i_znaki_specjalne}
.